How to Generate Random String of Fixed Length in Golang
Jay Singh
Feb 02, 2024
Many different algorithms need the production of random strings of a specific length. This article will show you how to produce a random string of a fixed length in Golang in several different methods.
Use math/rand to Generate Random String of Fixed Length in Golang
Go’s math/rand package provides pseudorandom number generation. We’ll use the package in this example and pass a random string to receive the output of a fixed-length string.
package main
import (
"fmt"
"math/rand"
)
func main() {
fmt.Println(RandomString(30))
}
func RandomString(n int) string {
var letterRunes = []rune("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
b := make([]rune, n)
for i := range b {
b[i] = letterRunes[rand.Intn(len(letterRunes))]
}
return string(b)
}
Output:
XVlBzgbaiCMRAjWwhTHctcuAxhxKQF
For another example, the method accepts a string containing each letter and produces a string by picking a letter at random from it.
package main
import (
"fmt"
"math/rand"
)
func RandomString(n int) string {
var letters = []rune("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789")
s := make([]rune, n)
for i := range s {
s[i] = letters[rand.Intn(len(letters))]
}
return string(s)
}
func main() {
fmt.Println(RandomString(13))
}
Output:
BpLnfgDsc2WD8
Let’s have a last example to fully understand how to generate a fixed-length string in Golang.
package main
import (
"fmt"
"math/rand"
)
func main() {
fmt.Println("Random String")
fmt.Println()
fmt.Println("11 chars: " + RandomString(11))
fmt.Println("20 chars: " + RandomString(20))
fmt.Println("32 chars: " + RandomString(32))
}
func RandomString(n int) string {
var letter = []rune("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789")
b := make([]rune, n)
for i := range b {
b[i] = letter[rand.Intn(len(letter))]
}
return string(b)
}
Output:
Random String
11 chars: BpLnfgDsc2W
20 chars: D8F2qNfHK5a84jjJkwzD
32 chars: kh9h2fhfUVuS9jZ8uVbhV3vC5AWX39IV