How to Get the Size of Array in C

Satishkumar Bharadwaj Feb 02, 2024
  1. sizeof() Operator to Determine the Size of an Array in C
  2. Get Length of Array in C
How to Get the Size of Array in C

This tutorial introduces how to determine the length of an array in C. The sizeof() operator is used to get the size/length of an array.

sizeof() Operator to Determine the Size of an Array in C

The sizeof() operator is a compile-time unary operator. It is used to calculate the size of its operand. It returns the size of a variable. The sizeof() operator gives the size in the unit of byte.

The sizeof() operator is used for any data type such as primitives like int, float, char, and also non-primitives data type as an array, struct. It returns the memory allocated to that data type.

The output may be different on different machines like a 32-bit system can show different output and a 64-bit system can show different of the same data types.

Syntax of sizeof():

sizeof(operand)
  • The operand is a data-type or any operand.

sizeof() Operator for Primitive Data Types in C

This program uses an int, float as a primitive data type.

#include <stdio.h>

int main(void) {
  printf("Size of char data type: %u\n", sizeof(char));
  printf("Size of int data type: %u\n", sizeof(int));
  printf("Size of float data type: %u\n", sizeof(float));
  printf("Size of double data type: %u\n", sizeof(double));

  return 0;
}

Output:

Size of char data type: 1
Size of int data type: 4
Size of float data type: 4
Size of double data type: 8

Get Length of Array in C

If we divide the array’s total size by the size of the array element, we get the number of elements in the array. The program is as below:

#include <stdio.h>

int main(void) {
  int number[16];

  size_t n = sizeof(number) / sizeof(number[0]);
  printf("Total elements the array can hold is: %d\n", n);

  return 0;
}

Output:

Total elements the array can hold is: 16

When an array is passed as a parameter to the function, it treats as a pointer. The sizeof() operator returns the pointer size instead of array size. So inside functions, this method won’t work. Instead, pass an additional parameter size_t size to indicate the number of elements in the array.

#include <stdio.h>
#include <stdlib.h>

void printSizeOfIntArray(int intArray[]);
void printLengthIntArray(int intArray[]);

int main(int argc, char* argv[]) {
  int integerArray[] = {0, 1, 2, 3, 4, 5, 6};

  printf("sizeof of the array is: %d\n", (int)sizeof(integerArray));
  printSizeOfIntArray(integerArray);

  printf("Length of the array is: %d\n",
         (int)(sizeof(integerArray) / sizeof(integerArray[0])));
  printLengthIntArray(integerArray);
}

void printSizeOfIntArray(int intArray[]) {
  printf("sizeof of the parameter is: %d\n", (int)sizeof(intArray));
}

void printLengthIntArray(int intArray[]) {
  printf("Length of the parameter is: %d\n",
         (int)(sizeof(intArray) / sizeof(intArray[0])));
}

Output (in a 64-bit Linux OS):

sizeof of the array is : 28 sizeof of the parameter is : 8 Length of the array
    is : 7 Length of the parameter is : 2

Output (in a 32-bit Windows OS):

sizeof of the array is : 28 sizeof of the parameter is : 4 Length of the array
    is : 7 Length of the parameter is : 1

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