How to try Without except in Python

Samyak Jain Feb 02, 2024
How to try Without except in Python

Exceptions in Python are the errors detected during the execution of the code. Different types of exceptions are NameError, TypeError, ZeroDivisionError, OSError and more.

The try statement in Python is used to test a block of code for exceptions, and the except statement is used to handle those exceptions. When the code in the try block raises an error, the code in the except block is executed.

We can catch all the exceptions, including KeyboardInterrupt, SystemExit and GeneratorExit. This method should not be used to handle exceptions since it is a general statement and will hide all the trivial bugs.

We will discuss how to use the try block without except in Python. To achieve this, we should try to ignore the exception.

We cannot have the try block without except so, the only thing we can do is try to ignore the raised exception so that the code does not go the except block and specify the pass statement in the except block as shown earlier. The pass statement is equivalent to an empty line of code.

We can also use the finally block. It will execute code regardless of whether an exception occurs or not.

try:
    a = 1 / 0
except:
    pass
finally:
    print("Example")

Output:

Example

In the above code, if the try block raises an error, the except block will print the raised exception.

To ignore exceptions, we can use the suppress() function from the contextlib module to handle exceptions in Python

The suppress() function from the contextlib module can be used to suppress very specific errors. This method can only be used in Python 3.

For example,

from contextlib import suppress

with suppress(IndexError):
    a = [1, 2, 3]
    a[3]

In the above example, it will not raise the IndexError.

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